Asked me to write 8 bytes aligned malloc and corresponding free function

Question

int *ptr = (int *) malloc(sizeof(int) * 2); · Accepted Answer

one int = 4 bytes.

Anoniem · Answer

void *aligned_malloc(int size, int align)
{
    void *p = malloc(sizeof(void *) + size + align);
    size_t mask = ~(align - 1);
    
    size_t p2 = ((size_t)p + align + sizeof(void *)) & mask;
    *((void **)p2 - 1) = p;
    return (void *)p2;
}

void aligned_free(void *p)
{
    void *p1 = *((void **)p - 1);
    
    free(p1);
}

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