enter any odd positive no . and do output as
n=3
@@@ @@@
@@@***@
@@@ @@@
n=5
@@@@@ @@@@
@@@@@ @
@@@@@*****@
@@@@@ @
@@@@@ @@@@@

Question

enter any odd positive no . and do output  as
n=3
@@@ @@@
@@@***@
@@@ @@@
n=5
@@@@@ @@@@
@@@@@              @
@@@@@*****@
@@@@@            @
@@@@@ @@@@@

Aayush Bhatt · Accepted Answer

#include 

int main()
{
    int i,j,n;
    //int n=5;
    
    
    printf("enter a number");
    scanf("%d",&n);
    int dk=n/2+1;
    
    for(i=1;i<=n;i++)
    {
        for(j=1;j<=n;j++){printf("@");}         //left side side
        for(j=1;j<=1;j++){printf(" ");}         //spaces
        if((i==1) || (i==n))                    //for first and last line of right side
        {
            for(j=1;j<=n;j++){printf("@");}
        }
        else if(i==dk){                         //for midline of right side
            for(j=1;j<=n;j++){printf("*");}
            printf("@");
        }
        else{                                   //for remaining lines of right side
            printf("@");
        }
        printf("
");
    }

    return 0;
}

Anoniem · Answer

#include 

int main(void) {
	// your code goes here
	int a=7;
	int d= a/2+1;
	for(int i=1;id)
		{
			printf(" ");
		}
		if(i==1 || i==a)
		{
			for(int k=1;k<=a;k++)
			{
				printf("@");
			}
		}
		else if(i==d)
		{
			for(int m=1;m<=a;m++)
			{
				printf("*");
			}
			printf("@");
		}
		else
		{
			printf("@");
		}
		printf("
");
	}
	return 0;
}

vikash kumar gupta · Answer

n=int(input("enter the number"))
z=int(n/2)
print("@"*n,"@"*n)
for i in range(0,z-1):
    print("@"*n,"@")
print("@"*n,"*"*n,"@")
for i in range(0,z-1):
    print("@"*n,"@"*n)

Ritesh Kumar · Answer

def fun(number):
    at_rate="@"*number
    for x in range(number):
        if x%2==0:
            continue
        if x==1:
            print(at_rate+" "+at_rate)
        else:
            print(at_rate+" "+"@")
    print(at_rate+"*"*number+"@")
    for x in reversed(range(number)):
        if x%2==0:
            continue
        if x==1:
            print(at_rate+" "+at_rate,end="")
        else:
            print(at_rate+" "+"@",end="")
        print("")
fun(5)

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